President Saakashvili will leave for the United States on September 20 to participate in the session of the UN General Assembly.

According to President’s administration, Saakashvili will address the UN General Assembly on September 23.

He will also make a speech at the New York University and participate in special receptions arranged on behalf of UN Secretary General and President Obama.

During the visit Saakashvili will also hold bilateral meetings with his counterparts from European, Latin American and African countries.